# Analog and Digital Electronics 4

Electrical Engineering MCQ Question Papers: Campus Placement

Subject: Analog and Digital Electronics 4

Part 4: List for questions and answers of Analog & Digital Electronics

Q1.In NAND logic analysis procedure application used are of

a) Truth table

b) Feedback theorem

c) Demorgan’s theorem

d) K-map

Q2.Circuits whose output depends on directly present input is called

a) Combinational circuit

b) Sequential circuit

c) Combinational sequence

d) Series

Q3.Full subtract or is a

a) Combinational circuit

b) Sequential circuit

c) Combinational sequence

d) Series

Q4.In first step of design procedure

a) Truth table is drawn

b) Circuit simplified

c) Circuit is drawn

d) Problem is stated

Q5.Most significant bit of arithmetic addition is called

a) Overflow

b) Carry

c) Output

d) Zero bit

Q6.Flip flop are constructed using

a) AND gate

b) OR gate

c) NAND gate

d) NOR gate

Q7.Two bit addition is done by

Q8.AND gates are converted to NAND gates using

a) Invert OR

b) AND invert

c) NAND invert

d) Both a and b

Q9.In map dont cares input are marked by

a) 0

b) 1

c) star

d) X

Q10.Not operation is obtained by using one input

a) AND gate

b) OR gate

c) NAND gate

d) NOR gate

Q11.Borrow in two bit (x,y) subtraction is 0, as long as

a) y greater than y

b) x equals to

c) x greater than equal to y

d) y greater than equal to x

Q12.To check circuits as combinational not sequential is a analysis procedure’s

a) 1st step

b) 2nd step

c) 3rd step

d) 4th step

Q13.Code not included in code conversion standard is

a) BCD code

b) Gray code

c) Excess3 code

d) Truth table

Q14.OR gates are converted to NAND gates using

a) Invert OR

b) AND invert

c) NAND invert

d) both a and b

Q15.To implement Boolean function with NAND gates we convert function to

a) AND logic

b) OR logic

c) NOR logic

d) NAND logic

Q16.In real design procedure we consider

a) Max no of gates

b) Min no of gates

c) Two gates

d) Three gates

a) 2 bits

b) 3 bits

c) 4 bits

d) 5 bits

Q18.When both inputs are different output of xor is

a) 1

b) 0

c) x

d) 10

Q19.Convenient way is to convert NAND logic diagram to its

a) AND diagram

b) OR diagram

c) AND-OR diagram

d) NOR diagram

Q20.Result of two bit subtract or is called

a) Difference bit

b) Least significant bit

c) Most significant bit

d) Carry bit

Part 4: List for questions and answers of Analog & Digital Electronics